Big Bach Posted November 10, 2011 Report Share Posted November 10, 2011 Bonjour, j’étais sur un exercice de dimensionnement de poutre; je dois passer par la formule W>Mfmax/Contrainte admissible Ici W= ((2a)^3)/3 avec a= largeur de la poutre Mfmax= 13.3 N.m Contrainte admissible= 10Mpa Je bloque pour convertir les Mpa en N.m ou faire de tel façon que le moment et la contrainte aient une même unité Aidez moi svp Merci beaucoup Quote Link to comment Share on other sites More sharing options...
abdeslam-brahim Posted November 10, 2011 Report Share Posted November 10, 2011 Quote Link to comment Share on other sites More sharing options...
abdeslam-brahim Posted November 10, 2011 Report Share Posted November 10, 2011 Quote Link to comment Share on other sites More sharing options...
Big Bach Posted November 11, 2011 Author Report Share Posted November 11, 2011 Quote Link to comment Share on other sites More sharing options...
sidoo Posted November 11, 2011 Report Share Posted November 11, 2011 Quote Link to comment Share on other sites More sharing options...
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