biaggi Posted March 26, 2018 Report Share Posted March 26, 2018 Bonjour à tous je cherche à calcul la charge admissible (en kg/m²) d'une voûte en pierre enterrée j'ai le croquis les pierres font 35 cm d'épaisseur avec 1 MPa de résistance au dessus de la voûte, il y a environ 60 cm de terre (1700kg/m3) j'ai commencé avec la formule P= 500efC/L P=500x0,35x1,1x1/3,4= 57 t/ml (pour la voûte en pierre seule, sans compter le poids de la terre au dessus) ca semble correct? 1 Quote Link to comment Share on other sites More sharing options...
Expert philkakou Posted March 27, 2018 Expert Report Share Posted March 27, 2018 (edited) Edited March 27, 2018 by philkakou 4 Quote Link to comment Share on other sites More sharing options...
gerard demeusy Posted March 28, 2018 Report Share Posted March 28, 2018 1 Quote Link to comment Share on other sites More sharing options...
Expert philkakou Posted March 30, 2018 Expert Report Share Posted March 30, 2018 (edited) Edited March 30, 2018 by philkakou Quote Link to comment Share on other sites More sharing options...
Expert philkakou Posted March 30, 2018 Expert Report Share Posted March 30, 2018 Quote Link to comment Share on other sites More sharing options...
gerard demeusy Posted March 30, 2018 Report Share Posted March 30, 2018 Quote Link to comment Share on other sites More sharing options...
Flyer Man Posted December 3, 2018 Report Share Posted December 3, 2018 Quote Link to comment Share on other sites More sharing options...
BELLAMINE Posted December 3, 2018 Report Share Posted December 3, 2018 1 Quote Link to comment Share on other sites More sharing options...
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BELLAMINE Posted December 5, 2018 Report Share Posted December 5, 2018 1 Quote Link to comment Share on other sites More sharing options...
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